princessnqueen

引用:

原帖由 No.2 於 2007-2-3 06:54 PM 發表
使用Scientific計數機
交換與組合(Permutations and Combinations)
交換(Permutations)適合計算有位置交換的可能性(如三重彩的有指定位置)
        nPr=n!/(n-r)!
n=總數, r=組合之數目
0!=1!=1
2!=1x2
...

Single Race Trio Chance

No. of Horse in the Race	Perecent of Trio Won (3 horses chosen)
6	5%
7	2.86%
8	1.79%
9	1.19%
10	0.833%
11	0.602%
12	0.455%
13	0.350%
14	0.275%

For example, if you try to select 3 horses from 3 races which have 12, 13 and 14 horses respectively... the chance will be

0.455% x 0.350% x 0.275%
= 0.00455 x 0.00350 x 0.00275
= 0.00000004379375
= 0.000004379375%
or about 1 / 22834309

princessnqueen

引用:

原帖由 No.2 於 2007-2-8 05:05 AM 發表
please give me the mathematical model!
proof it!

you already made the proof in your first message, don't you?
i just subbed the number in ... 6C3, 7C3 .... and so on up to 14C3 and made it in percentage form.

The end result is to make people to know their winning chance.  I am not sure how many people will do the math here although I respected you for your intention :096: :098: